#2496. Very Boring Homework

  Prof. Z thinks his homework is very hard for most of his students to solve (do you remember the task “Boring Homework”?) To his surprise, many students hand in correct solutions. He thinks the reason is actually the small size of the data set he used to test students’ programs rather than the low difficulty of the homework task. He decides to give his students the same homework again, but with enormous test cases. Of course, his students think his homework becomes even more boring this time. They need your help again.
  For the ones who don’t know what homework Prof. Z. had given to his students last time:
  
  You’re asked to draw a graph of a binary search tree (BST).

  A binary search tree, which may sometimes also be called ordered or sorted binary tree, is a node-based binary tree data structure which has the following properties:
  The left subtree of a node contains only nodes with keys less than the node's key.
  The right subtree of a node contains only nodes with keys greater than the node's key.
  Both the left and right subtrees must also be binary search trees.
  --from Wikipedia

  Given a list of integer keys that should be inserted into the BST one by one orderly, we can form a unique BST. Moreover, Prof. Z wants the students to draw the graph of this BST.
  
  The rules to draw a graph of a BST are listed below:
  
1. The graph of a 1-node BST is a single 'o' (15th small Latin letter).
2. If a BST has a non-empty subtree, draw a single '|' just above the subtree's root, and a single '+' just above the previous drawn '|'. Finally, in the row of '+', use the least number (including 0) of '-'s to connect '+' (corresponding to the left or right subtree) and 'o' (denoting the parent node of the subtrees).
3. The left subtree (if exists) must be drawn on the left side of its parent. Similarly, the right subtree (if exists) must be drawn on the right side of its parent.
4. The column of the BST's root must not contain any characters belonging to left or right subtree.
5. For each node of the BST, the graph of its left subtree and the graph of its right subtree do not share common columns in the picture of the whole tree.

  After the whole BST has been drawn, we number the rows from top to bottom, counting from 1, and so do the columns from left to right, counting from 1.
  Due to the large scale of the tree, the graph will become so large that it is impossible for Prof. Z to check every detail of the graph this time. So you are only asked to hand in m fragments of that graph to Prof. Z instead of the whole one.

根据输入构造一棵二叉树，将二叉树转化为图形，并根据询问输出该图形的局部

样例输入

			
3

3

3 1 2

1

1 1 5 3

6 4 5 6 1 3 2

1

1 1 8 10

10

2 6 7 4 5 3 1 9 10 8

2

1 1 5 5

3 6 5 5

 



 

样例输出

			
Case #1:

+-o

|  

o+ 

 | 

 o 



Case #2:

+--o+     

|   |     

o-+ o+    

  |  |    

 +o  o    

 |        

 o        



Case #3:

+o---

|    

o  +-

   | 

  +o+



o+   

 |   

 o-+ 

   | 

  +o+