4 6 4 3 3 5 2 5 2 4
9
An available assignment is the first two pairs are assigned into the first part and the last two pairs are assigned into the second part. Then B1 > A3, B1 > A4, B2 > A3, B2 > A4, max{A1, A2}+max{A3, A4} ≤ 6, and minimum max{B1+B2, B3+B4}=9.
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